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Determine the solution set of x^2-80=0.

asked
User Sdanzig
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2 Answers

3 votes
x^2 - 80 = 0
x^2 = 80 ...take the square root of both sides, eliminating the ^2
x = (+-) sqrt 80
x = (+-) sqrt 16 * 5
x = (+-) 4 sqrt 5

so x = 4 sqrt 5 or x = -4 sqrt 5
answered
User Xueru
by
8.3k points
6 votes

Answer: The required solution set of the given equation is
\{4\sqrt5,-4\sqrt5\}.

Step-by-step explanation: We are given to determine the solution set of the following quadratic equation :


x^2-80=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Since the given equation does not contain the term involving x, so we will use the method of square root to solve the given equation.

The solution of equation (i) is as follows :


x^2-80=0\\\\\Rightarrow x^2=80\\\\\Rightarrow x=\pm√(80)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{taking square root on both sides}]\\\\\Rightarrow x=\pm√(16*5)\\\\\Rightarrow x=\pm4\sqrt5.

Thus, the required solution set of the given equation is
\{4\sqrt5,-4\sqrt5\}.

answered
User Maulana Prambadi
by
7.3k points

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