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Write the equation in spherical coordinates. 3x + 2y + 3z = 1

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\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\cos\varphi\end{cases}


3x+2y+3z=1

\implies3\rho\cos\theta\sin\varphi+2\rho\sin\theta\sin\varphi+3\rho\cos\varphi=1

\implies\rho=\frac1{(3\cos\theta+2\sin\theta)\sin\varphi+3\cos\varphi}
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User Pangamma
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