Question

The perimeter of a rectangular painting is 332 centimeters. if the length of the painting is 92 centimeters, what is its width?

Answer 1

Answer: The width of the rectangular painting is: " 74 cm " .
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Step-by-step explanation:
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P = 2L + 2w ;

in which: P = perimeter = 332 cm (given) ;
L = length = 92 cm (given) ;
w = width = ? (to be solved) ;
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First, given: P = 2L + 2w ;

Subtract "2L" from EACH SIDE of the equation ;
to isolate "2w" on one side of the equation ;
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P − 2L = 2L + 2w − 2L ;

to get: P − 2L = 2w ;

↔ 2w = P − 2L ;

Now:
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Plug in our given values into the equation / formula ; and solve for "w" ;

2w = 332 − 2(92) ;

2w = 332 − 184 ;

2w = 148 ;

Now, divide EACH SIDE of the equation by "2" ;
to isolate "w" on one side of the equation ; and to solve for "w" ;
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2w / 2 = 148 / 2 ;

w = 74 cm .
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