Question

The population for Gulch Dry has been declining according to the function P(t)= 8000. 2^-t/29 where t is the number of years since 1910

a) what was the town's population in 1990
b) in what year will the town's population first fall under 125 people?

Answer 1

a)


`\bf 1990-1910=80\leftarrow t \\\\\\ P(t)=8000(2)^{-(t)/(29)}\implies P(80)=8000(2)^{-(80)/(29)} \\\\\\ P(80)=8000\cdot \cfrac{1}{2^{(80)/(29)}}\implies P(80)=\cfrac{8000}{\sqrt[29]{2^(80)}}`

and surely you know how much that is.

b)


`\bf P(t)=125\\\\\\ 125=8000(2)^{-(t)/(29)}\implies \cfrac{125}{8000}=2^{-(t)/(29)}\implies \cfrac{1}{64}=2^{-(t)/(29)} \\\\\\ \textit{now we take log to both sides} \\\\\\ log\left( (1)/(64) \right)=log\left( 2^{-(t)/(29)} \right)\implies log\left( (1)/(64) \right)=-(t)/(29)log\left( 2 \right) \\\\\\ log\left( \cfrac{1}{64} \right)=-\cfrac{tlog(2)}{29}\implies \cfrac{-29log\left( (1)/(64) \right)}{log(2)}=t\implies 174=t`

since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.