First problem.
Call a and b the sides. Since the sides are doubled they are 2*a and 2*b
You know the area is given by a*b.
2a*2b = 12
4ab = 12
So divide both terms for 4 :)
ab = 3 ft^2
Second problem.
Find the volume of the two solids.
The first contenitor is a parallelepiped.
V = abh
a = 10
b = 5
h = 6
V = 10*5*6 = 300 in^3
The second solid is a cilinder.
V = pi*r^2*h = 3^2*10*pi = 9*10*pi = 90pi in^3 = 90*3,14 = 282,6 in^3
The first contenitor hold more ice cream