Value for X^2 left for 95% confidence interval when n=18

Question

asked Oct 23, 2018 95.1k views

1 Answer

Sarath · Answer 1 · 2018-10-27T07:57:19+0000

Given that n = 18, then the degree of freedom is n - 1 = 17.

From the table of Chi Square
(X^2)

The value of
(X^2)

to the left for 95% confidence interval given a degree of freedom of 17 is 8.672