Question

Helpiii A gas occupies a 16-liter balloon under a pressure of 1.2 atm. what would the new volume of the balloon be if the pressure were increased to 3.6 atm?

Answer 1

This is an example of Boyle's Law (P1V1=P2V2)

The answer is 5.33 liters.

Hope this helps.

Answer 2

The new volume shall be 5.33 liter

Step-by-step explanation:

First thing's first, we bring out the parameters mentioned in the question.

We have;

Initial Volume (V1) = 16L

Initial pressure (P1) = 1.2 atm

Final Volume (V2) = ?

Final Pressure (P2) = 3.6atm

Upon looking at the parametwes, we can deduce that we would apply the boyles law because it is the law that relates both parameters (Volume and Pressure).

Boyles's law states that the volume of a fixed mass of gas is inversely proportional to the pressure provided temperature reamins contant.

The mathematical representation is given as;

P1V1 = P2V2

Making V2 subject of interest, we have;

V2 = P1V1 / P2

V2 = (1.2 * 16) / 3.6

V2 = 19.2 / 3.6

V2 = 5.33L