Question

Find the quotient of quantity of 3 times x to the 3rd power plus 9 times x to the 2nd power minus 6 times x all over negative 3 times x

Answer 1

-x^2 -3x + 2
------------------------------
-3x ) 3x^3 + 9x^2 - 6x
3x^3
9x^2
-6x

answer is -x^2 - 3x + 2

Answer 2

Quotient = -x² -3x +2.

Explanation:

Given : quantity of 3 times x to the 3rd power plus 9 times x to the 2nd power minus 6 times x all over negative 3 times x.

To find : Find the quotient.

Solution : We have given that statement

3 times x to the 3rd power = 3x³.

9 times x to the 2nd power =9x²

6 times x = 6x

3x³ +9x²-6x over -3x.

On dividing 3x³ +9x²-6x by -3x

`(3x^(3))/(-3x) +(9x^(2))/(-3x) -(6x)/(-3x)` .

On cancel out the like numertor and denominator.

Quotient = -x² -3x +2

Therefore, Quotient = -x² -3x +2.