Question

The area of a triangular flag is 4242 square centimeters. its altitude is 2 centimeters longer than twice its base. find the lengths of the altitude and the base.

Answer 1

A = (h * b) / 2
h = 2b + 2
A = 42

42 = (b(2b + 2)) / 2
42 = (2b^2 + 2b) / 2
42 = b^2 + b
b^2 + b - 42 = 0
(b + 7)(b - 6) = 0

b + 7 = 0
b = -7...nope..extraneous solution

b - 6 = 0
b = 6 <== base

h = 2b + 2
h = 2(6) + 2
h = 12 + 2
h = 14 <=== height (altitude)