Question

Suppose the population of a town is 567 in 2001. The population decreases at a rate of 1.5% every year. What will be the population of the town in 2010? Round your answer to the nearest whole number.

Answer 1

I think this question is about exponential growths and decays.

1.5% ⇒ 0.015

f(x) = 567(1- 0.015)^9
f(x) = 567(.985)^9
f(x) = 494.890518539

Since we are talking about population, we round. Therefore, the population of the town is 495 in 2010.