Question

Find the quotient of the quantity 21 times x to the 2nd power times y to the 6th power plus 6 times x times y to the 3rd power minus 30 times x times y all over 3 times x times y. 21x2y6 + 6xy3 − 10 7xy5 + 2y2 + 10 7xy5 + 2y2 − 10 7xy5 + 2y − 10

Answer 1

`\cfrac{21x^2y^6+6xy^3-30xy}{3xy} = \cfrac{3xy(7xy^5+2y^2-10)}{3xy} =7xy^5+2y^2-10`

Answer 2

Option C.
`7xy^(5)+2y^(2)-10` is the answer.

Explanation:

The given fraction is
`(21x^(2)y^(6)+6xy^(3)-30xy)/(3xy)`.

We have to find the quotient. As we know quotient is the net result of division of any fraction, so we will solve the fraction to get the value of quotient.

`(3xy(7xy^(5)+2y^(2)-10))/(3xy)`

`7xy^(5)+2y^(2)-10`

Therefore the quotient is Option C.
`7xy^(5)+2y^(2)-10`.