asked 66.4k views
1 vote
Two triangles.are.similar, solve for x if au=20x +108, ub=273, bc= 703, uv=444, AV = 372 and AC=589

1 Answer

3 votes

If two triangles are similar then the corresponding sides are in proportion. Thus,

AB / AU = BC / UV = AC / AV

AB / (20x+108) = 703 / 444

Where AB is equivalent to:

AB = AU + UB

AB = 20x + 108 + 273

AB = 20x + 381

Therefore going back to the first equation:

(20x + 381) / (20x + 108) = 703/444

444 (20x + 381) = 703 (20x + 108)

8880x + 169164 = 14060x + 75924

14060x - 8880x = 169164 – 75924

5180 x = 93240

x = 93240 / 5180

x = 18 (ANSWER)

answered
User Fernando Almeida
by
7.9k points
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