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Factors of 3x^2y^2+6x^2+12y^2+24

1 Answer

4 votes
look for the GCF

GCF = 3

so we have

3 (x^2y^2 + 2x^2 + 4y^2 + 8) Factor by grouping:-

= 3[ x^2(y^2 + 2) + 4(y^2 + 2)]

= 3(x^2 + 4)(y^2 + 2)
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User Jjharrison
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