Question

The area behind the free throw line on a basketball court is a semicircle with a 6-foot radius. What is the area of the semicircle?

Answer 1

thx

Explanation:

Answer 2

Since the area of a circle is:

A=πr^2

And we only want half of the area, a:

a=(πr^2)/2, and we are given that r=6

a=(π6^2)/2

a=36π/2

a=18π ft^2

a≈56.55 ft^2 (to nearest hundredth of a square foot)