Question

If 38.7 grams of lithium chlorate decomposes, how many grams of oxygen gas can be produced?

2LiClO3 → 2LiCl + 3O2


41.1 g O2
20.6 g O2
9.13 g O2
6.85 g O2

Answer 1

The answer to your question is 20.6

Answer 2

LiClO3 has mole of mass of 90 g/mol

So 38.7 g means 0.43 mol

Since in this reaction, LiClO3 : O2 = 2:3, then it will produce 0.43*3/2 = 0.645 mol O2

So it is equivalent to 0.645 * 32 = 20.64 g O2