Question

Someone please solve this ASAP and give answer as a square root

Answer 1

Given pyramid with a regular hexagonal base,
side length=6
`√(3)` cm
Height = 4 cm

We need to find the area of the hexagonal base. First step is to find the apothm,
a=side*(
`√(3)/2`
=6*3/2=9
So the area of each equilateral triangle making up the base
=base*apothem/2
=6
`√(3)` *9/2
=27
`√(3)`
The area of base = 6 area of each triangle
=6*27
`√(3)`
=162
`√(3)`

Volume of pyramid = area of base * height /3
=162
`√(3)`*4/3
=216
`√(3)`