Question

A complex number, (a + bi), multiplied by (2 + 3i) and added to -i gives the product of (-11 +5i) and (1-i)

a= ? b=?

Answer 1

working backwards (-11 + 5i)(1 - i) = -11 + 11i + 5i +5 = -6 + 16i

subtracting -i we have -6 +16i - (-i) = -6 + 17i


(a + bi)(2 + 3i) = 2a + 3ai + 2bi + 3bi^2 = 2a - 3b + (3a + 2b)i

2a - 3b + (3a + 2b)i = -6 + 17i

EQuating real and imaginary parts:-

2a - 3b = - 6
3a + 2b = 17

solving this for a and b gives a = 3 and b = 4