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Prove that for all natural numbers n 8n-3n is divisible by 5

Prove that for all natural numbers n 8n-3n is divisible by 5
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Prove that for all natural numbers n 8n-3n is divisible by 5

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User Jay Regal
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2 Answers

3 votes


8n-3n=5n

One of the factors is 5, so the number is divisible by 5.

answered
User Nimesh Nikum
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7.8k points
4 votes
8n-3n=n(8-3)=n(5)=5n=5 times n
5 is a factor of 5n so it is evenly divisible by 5
and since n is a natural number, it is the multiplier to make multipules of 5

answered
User Havald
by
7.8k points
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