4x2 + 15 + 4x + 15 + 4x2 + 15 + 4x + 15 +

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asked Sep 4, 2018 13.4k views

2 Answers

Zoltan Fedor · Answer 1 · 2018-09-08T11:32:23+0000

This can be done by synthetic division since the divisor is in the form (x - #) or (x + #).

__________
3 | 4 3 2

12 45
------------------
4 15 47

4x + 15 + 47/(x-3)

divisor or d(x) = (x - 3)
quotient or q(x) = 4x + 15
remainder or r(x) = 47/(x - 3)

4x2 + 15 + 4x + 15 + 4x2 + 15 + 4x + 15 +

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