We are given that:
 m0 = initial mass of rocket = 25.3 g
 t = duration of the burn = 1.90 s
  
 T = average thrust = 5.26 N
 mFu = mass of fuel = 12.8 g
 First we calculate the final mass after 1.90 s (mF):
 mF = m0 – mFu = 25.3 g – 12.8 g = 12.5 g
 Then we calculate for the mass rate of fuel consumption, φm:
 φm = 12.8 g / 1.90 s =6.737 g /s
 To calculate for the average exhaust speed (vF), we use the derived formula:
 Δv = [T / φm] * ln(m0/mF)
 Since the rocket started from rest, therefore Δv = vF
 vF = [T / φm ] * ln(m0/mF)
 vF = [5.26 N / 6.737 x 10^-3 kg/s] * ln(25.3 g / 12.5 g)
 vF= 550.5 m/s