asked 116k views
2 votes
it takes 70 oz of grass seed to seed 2800ft of lawn. at this rate, how much would be needed for 3600 ft of lawn?

asked
User Sebin
by
8.7k points

1 Answer

3 votes
Find the multiplier to get from 2800ft to 3600ft. Multiply the weight of seed required for 2800ft by this multiplier for your answer.
3600/2800=9/7
70*9/7=90 oz
answered
User Samuel Ramzan
by
7.9k points

Related questions

1 answer
0 votes
16.3k views
1 answer
1 vote
58.5k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.