Question

The square root 41 is between two consecutive integers

Answer 1

√41≈6.4

So the two integers would be 6 and 7

*note that this is a poor question as the square root of 41 is ±√41≈±6.4, and integers can be positive or negative so technically the root is between -7 and -6 as well.

Answer 2

6 and 7 (root of 41 is about 6.403)