asked 168k views
5 votes
Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1?

asked
User Qxlab
by
7.8k points

2 Answers

3 votes
Root of 2i also means there is a root of -2i
Root of 3i also means there is a root of -3i

Factors will be (x^2 + 4)(x^2 + 9).
Multiply this out to get the polynomial:
x^4 + 13x^2 + 36
answered
User Jmurzy
by
7.9k points
1 vote

Answer:


Explanation:

f(x) = (x + 2i)(x + 3i)(x – 2i)(x – 3i)

Choice D.

answered
User Ankit Makwana
by
7.9k points
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