Question

Initially a beaker contains 225.0 ml of a 0.350 M MgSO4 solution. Then 175.0 ml of water are added to the beaker. Find the concentration of the final solution. What is the volume?

Answer 1

Final volume is 400 mL

The moles in MgSO4 is 0.00788 mL

The new concentration is 0.197

Answer 2

Answer : The concentration of final solution is, 0.197 M and the final volume of solution is, 400 ml

Solution :

First we have to calculate the final volume of solution.

Final volume of solution = Volume of
`MgSO_4` + Volume of water added

Final volume of solution = 225.0 ml + 175.0 ml = 400 ml

Now we have to calculate the concentration of final solution.

Formula used :

`C_1V_1=C_2V_2`

where,

`M_1` = concentration of
`MgSO_4` solution = 0.350 M

`V_1` = volume of
`MgSO_4` solution = 225.0 ml

`M_2` = concentration of final solution = ?

`V_2` = volume of final solution = 400 ml

Now put all the given values in the above formula, we get the concentration of final solution.

`(0.350M)* (225.0ml)=C_2* (400ml)`

`C_2=0.197M`

Therefore, the concentration of final solution is, 0.197 M