A 1000-kg car traveling at 66 m/s hits a 2000-kg car at rest and the two travel together after the collision. calculate the speed with which they move.

Question

asked Aug 9, 2018 123k views

2 Answers

John Park · Answer 1 · 2018-08-14T11:59:06+0000

Answer:

v = 22 m/s

Step-by-step explanation:

As we know that since there is no external force on the system of two cars

so we can say that momentum of two cars will be conserved

$F = 0 = (\Delta P)/(\Delta t)$

so here we can say

$\Delta P = 0$

so we have

P_i = P_f

m_1v_(1i) + m_2v_(2i) = (m_1 + m_2)v

1000(66) + 2000(0) = (1000 + 2000)v

v = 22 m/s

so we can say that final speed of both cars will be 22 m/s