Question

The length of a rectangle is 5 m less than twice the width, and the area is 33 m. Find the dimensions of the rectangle.

Answer 1

check the picture below

it can't be -3... since is width unit, so it has to be the other

and recall that length = 2w - 5

Answer 2

5 cm less than twice the width:


`l = 2w - 5`


`A = lw`


`33 = lw`


`33 = (2w - 5)(w)`


`33 = 2w^2 - 5w`


`2w^2 - 5w - 33 = 0`


`w = 5.5, -3`

-3 is an extraneous solution, so the only answer is
`w = 5.5`


`33 = 5.5l`


`\frac {33}{5.5} = ( (5.5)/(5.5))(l)`


`6 = l`

The dimensions of the rectangle are a length of 6, and a width of 5.5