Question

What is the approximate mass of 25 cm3 of silver, if the density is 10.5 g/cm3?

a.0.42 g
b.2.4 g
c.42 g
d.260 g

Answer 1

25 x 10.5 = 262.5

So the approx. is 260 g which is answer D.

Answer 2

Mass, m = 260 grams

Step-by-step explanation:

It is given that,

Density of silver,
`d=10.5\ g/cm^3`

Volume of the silver,
`V=25\ cm^3`

We need to find the mass of a piece of silver. The formula for the density is given by :

`d=(m)/(V)`

`m=d* V`

`m=10.5\ g/cm^3* 25\ cm^3`

m = 262.5 g

or

m = 260 grams

So, the mass of the piece of the silver is 260 grams. Hence, this is the required solution.