Question

The legs of an isosceles triangle measure 3 inches longer than its base the perimeter of the triangle is 30 inches write and solve an equation for the lengths of the three sides of the triangle

Answer 1

Leg 1 : 11
Leg 2 : 11
Leg 3 : 8

11 + 11 + 8 = 30

This can be determined using this equation:

30 = 2(x+3) + x

Solving:

30 = (x+3) + (x+3) + x
30 = 3x + 6
24 = 3x
/3 /3
8 = x

Leg 1: 8 (x) + 3 = 11
Leg 2: 8 (x) + 3 = 11
Base = 8