Question

Find the solution Sin(tan-1 0)

Answer 1

`\bf sin\left[ tan^(-1)(0) \right]\textit{ now, if }tan^(-1)(0)=\theta \textit{ that simply means }tan(\theta )=0 \\\\\\ tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\impliedby \begin{array}{llll} \textit{because of that, tangent is only 0}\\ \textit{when sine is 0} \end{array} \\\\\\ \textit{and sine is 0 only at }\quad \boxed{0,\pi ,2\pi} \textit{ on the interval of }[0,2\pi ]`