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Find the possible value or values of n in the quadratic equation 2n2 – 7n + 6 = 0.

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User Rssfrncs
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2n^2 - 7n + 6 = 0\\ 2n^2-4n-3n+6=0\\ 2n(n-2)-3(n-2)=0\\ (2n-3)(n-2)=0\\ n=(3)/(2) \vee n=2
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User SMshrimant
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