Question

What is oxidized and what is reduced in this reaction?

N2H4(l) + 2H2O2(l) → N2(g) + 4H2O(g)

N is reduced and H is oxidized.

N is reduced and O is oxidized.

N is oxidized and O is reduced.

N is oxidized and H is reduced.

Answer 1

the answer is C
N is oxidized and O is reduced

Answer 2

Answer: N is oxidized and O is reduced.

Step-by-step explanation:

`N_2H_4(l)+2H_2O_2(l)\rightarrow N_2(g)+4H_2O(g)`

Oxidation: Removal of hydrogen or addition of oxygen is termed as oxidation.

Reduction: Removal of oxygen or addition of hydrogen is termed as reduction.

In a given reaction,

• Removal of hydrogen from
  `N_2H_4` gives
  `N_2` gas which means nitrogen is getting oxidized.

• Whereas removal of oxygen from
  `H_2O_2` gives
  `H_2O` gas which means that oxygen is getting reduced.