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Find the zeros of y=x^2-4x-9 by completing the square

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User Zachzurn
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1 Answer

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x^2-4x-9=0\\ x^2-4x+4-13=0\\ (x-2)^2=13\\ x-2=-√(13) \vee x-2=√(13)\\ x=2-√(13) \vee x=2+√(13)
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User Henryabra
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