Question

A mixture of three noble gases has a total pressure of 1.25 atm the individual pressures exerted by neon and argon are 0.68 atm and 0.38 atm respectively.what is the partial pressure of the third gas ,helium

Answer 1

P = P1 + P2 + P3
1.25 = 0.68 + 0.38 + P3
P3 = 1.25 - 0.68 +0.38
P3 = 0.19

Or

Add the both known pressures 0.68 + 0.38 = 1.06
Know subtract the two gas pressures from the total pressure: 1.25 - 1.06 = 0.19atm
Hope that helps

Answer 2

Answer: 0.19 atm

Step-by-step explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

`p_(total)=p_1+p_2+p_3`

Given :
`p_(total)` = 1.25 atm

`p_(Ne)` = 0.68 atm

`p_(Ar)` = 0.38 atm

`p_(He)` = ?

`p_(total)=p_(Ne)+p_(Ar)+p_(He)`

Putting in the values:

`1.25=0.68+0.38+p_(He)`

`p_(He)=0.19atm`

Thus partial pressure of the third gas helium is 0.19 atm