How much heat is required to increase the temperature of 198.5 grams of water from 25.0 oC to 88.5 oC? (The specific heat of water is 4.18 J/g x oC) A.52, 700 J B.199 J C.265 J …

Question

asked Oct 22, 2018 179k views

2 Answers

Kenlyn · Answer 1 · 2018-10-26T14:34:08+0000

Answer : The correct option is, (A) 52700 J

Solution :

Formula used :

$Q= m* c* \Delta T$

Q = heat gained

m = mass of the substance = 198.5 g

c = heat capacity of water = 4.18 J/g°C

$\Delta T=\text{Change in temperature}=(88.5-25)^oC=63.5^oC$

Now put all the given values in the above formula, we get

Q=198.5g* 4.18J/g^oC*63.5^oC

Q = 52687.855 J ≈ 52700 J

Therefore, the amount of heat required is, 52700 J