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There are 5 comedy, 8 action, and 11 children DVDs on a rack. Susan randomly selects 3 of them. What is the probability that she selects a comedy, followed by an action, then a …

There are 5 comedy, 8 action, and 11 children DVDs on a rack. Susan randomly selects 3 of them. What is the probability that she selects a comedy, followed by an action, then a …
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There are 5 comedy, 8 action, and 11 children DVDs on a rack. Susan randomly selects 3 of them. What is the probability that she selects a comedy, followed by an action, then a children's?

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User Leonardofed
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|\Omega|=24\cdot23\cdot22=12144\\ |A|=5\cdot8\cdot11=440\\\\ P(A)=(440)/(12144)=(5)/(138)
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User Mark Spangler
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