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In ABC, AB=3 and AC=9 find m<B to the nearest degree

In ABC, AB=3 and AC=9 find m<B to the nearest degree
asked 9.2k views
5 votes
In ABC, AB=3 and AC=9 find m<B to the nearest degree

In ABC, AB=3 and AC=9 find m<B to the nearest degree-example-1
asked
User Giladbu
by
7.9k points

2 Answers

3 votes

Answer: 72° (nearest degree)

answered
User Cotten
by
8.0k points
5 votes
By definition,
tanB = opposite/adjacent = 9/3 = 3

From the calculator,
B = arctan(3) = 71.6°

Answer: 72° (nearest degree)
answered
User Brunovianarezende
by
9.0k points
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