Question

The area of a rectangle is 52 yd2 , and the length of the rectangle is 5 yd less than twice the width. find the dimensions of the rectangle.

Answer 1

Let's say the rectangle's dimensions are l and w.
Then:

wl = 52
l = 2w-5

This we can solve:

w(2w-5) = 52
2w² - 5w - 52 = 0

Using the quadratic formula you can find w = 13/2
So l = 8