Question

The length of a rectangle is four times its width.

If the area of the rectangle is 144 yd^2, find its perimeter.

Answer 1

hello;
x is the length , y the width :
x = 4y...(1)
xy = 144....(2)
subsct in (2) : 4y(y) = 144
y² = 36
y = 6 yd so : x = 24 yd
the perimeter is : 2(6+24) =60 yd