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A tour boat left the dock and traveled west at an average speed of 10 mph. A smaller fishing boat left some time later traveling in the same direction but at an average speed of 12 mph. After traveling for 10 hours, the fishing boat caught up to the tour boat. The tour boat left _______ hours earlier than the fishing boat.

A. 2
B. 11
C. 10
D. 18

asked
User Javimuu
by
8.8k points

2 Answers

4 votes

Answer:A2

Explanation:

answered
User Salexander
by
8.0k points
5 votes

Answer:

The answer is D.

Explanation:

Time = Distance / Speed

Distance = 12 *10 =120

Time = 120 / 12

Time = 10

Please correct if me if I'm wrong

answered
User Bshirley
by
9.4k points
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