PLEASEE HELP ANYONE Given the bag of marbles above, find the probability of first drawing a green marble and then drawing a blue marble, without replacing the first marble.

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asked Jul 2, 2018 149k views

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Buhake Sindi · Answer 1 · 2018-07-08T05:20:50+0000

We notice there are 4B and 4G (shown in the photo)

P(picking 1st a Green) = 4/8 (having picked a green -and not replacing it- the remaining number of marbles is 3G + 4B)

P(picking 2nd a Green) =3/7

P(picking 1st green AND picking 2nd Green )=(4/8) x (3/7) = 12/56≈ 0.21=21%

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PLEASEE HELP ANYONE Given the bag of marbles above, find the probability of first drawing a green marble and then drawing a blue marble, without replacing the first marble.

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