Question

2(3y − 1)(y − 3) is the factored form of

Answer 1

2(3y − 1)(y − 3) = (6y-2)(y-3) = 6y²-18y-2y+6 = 6y²-20y+6

Answer 2

Factored form is of (6y² - 20y + 6).

Explanation:

We have to find the expression of which factored form is 2(3y -1)(y -3).

We will further simplify these factors to get the original expression.

2(3y -1)(y - 3) = 2[3y(y - 3) - 1(y -3)]

= 2[ 3y² - 9y - y + 3]

= 2(3y² - 10y + 3)

= 6y² - 20y + 6

Therefore the factored form is of 6y² - 20y + 6.