Question

If 2.96 g of methane gas (CH4) is introduced into an evacuated 2.20 L container at 40.°C, what is the pressure in the container?

Answer 1

PV = nRT
n = m × 1/mm = 2.96g × 1moles/16g
n = 0.185 moles
P = nRT/V
P = (.185)(.0821)(313)/(2.2)
P = 4.754/2.2 = 2.161 atm