How many joules of heat are absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100.°C?

Question

asked Feb 13, 2018 47.8k views

1 Answer

Joseluisbz · Answer 1 · 2018-02-19T21:56:49+0000

E = mcT
m : mass
c: specific heat capacity of water
T : temperature change
E = 435 × 4.18 × (100-25)
= 136372.5 J

Hope it helped!