Question

The circle below is centered at the point (8, 4) and has a radius of length 4. What is its equation?

Answer 1

(x-8)^2 + (y-4)^2= 16

Answer 2

`(x-8)^(2)+(y-4)^(2)=16`

Explanation:

we know that

The equation of a circle into center radius form is equal to

`(x-h)^(2)+(y-k)^(2)=r^(2)`

where

(h,k) is the radius of the circle

r is the radius of the circle

In this problem we have

`r=4\ units`

`(h,k)=(8,4)`

substitute

`(x-8)^(2)+(y-4)^(2)=4^(2)`

`(x-8)^(2)+(y-4)^(2)=16`