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Compute the value of the discriminant and give the number of real solutions of the quadratic equation. -4x^2+3x+1=0

Compute the value of the discriminant and give the number of real solutions of the quadratic equation. -4x^2+3x+1=0
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Compute the value of the discriminant and give the number of real solutions of the quadratic equation. -4x^2+3x+1=0

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User LuckyTuvshee
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1 Answer

5 votes
-4x^2+3x+1=0
D = b² - 4ac = 3² - 4 * (-4) * 1 = 9 + 16 = 25
D>0 ⇒ this equation has two solutions.
answered
User Dan Gebhardt
by
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