Question

Find the equation of the line parallel to y=2x+1 that contains point (14,3)

Answer 1

First of all, remember what the equation of a line is:

`y=mx+b`

Where:

m=slope

b=y-intercept.

Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope

`y=2x+b`

To find b, think about what your (x,y) point means:(14,3). When x of the line is 14, y of the line must be 3.

Because we were given the point (14,3)
We need to find the value of b. The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).Plug in for x the number 14 and for y the number 3:
(14,3).
y=mx+b or 3=2 × 14+b,

solving for b: b=3-(2)(14). b=-25.Plug that in for b:
y=2x-25
Final answer:
y=2x-25