Question

The circumference of a bowling ball is 8pi in. Find the surface area of the bowling ball. Express your answer in terms of pi.

Answer 1

The surface area of a bowling ball with a circumference of 8pi inches is 64π square inches.

Step-by-step explanation:

To find the surface area of a bowling ball with a circumference of 8pi inches, we first need to determine the radius of the ball using the circumference formula:

Circumference (C) = 2πr

Dividing both sides of the equation by 2π gives us the radius (r):

r = C / (2π) = 8π inches / (2π) = 4 inches

Now we can use the surface area formula for a sphere:

Surface Area (A) = 4πr²

Substituting in the radius we found:

A = 4π(4 inches)² = 4π(16) = 64π square inches

So the surface area of the bowling ball expressed in terms of π is 64π square inches.

Answer 2

Surface area of a sphere (3D solid's name for ball shaped object) is given by


`SA = 4 \pi r^(2)`

We do not know the radius of the sphere but we can work it out from the circumference
`8 \pi`


`Circumference = 2 \pi r`

`8 \pi =2 \pi r`

`r= (8 \pi )/(4 \pi )=2`

then

`SA=4 \pi (2)^(2) =16 \pi`