Question

Subtract: 16a 2 - 32a + 9 from 12a 2 + 60a - 8.

Answer 1

12 a^2 + 60 a - 8
- (16 a^2 - 32 a + 9)

= -4 a^2 + 92 a - 17

Answer 2

`12a^2 + 60a -8-(16a^2 - 32a + 9)=-4a^2+92a-17`

Explanation:

Given : Polynomial
`16a^2 - 32a + 9` and
`12a^2 + 60a -8`

We have to subtract
`16a^2 - 32a + 9` from
`12a^2 + 60a -8`

Consider the given polynomials,

We have to subtract
`16a^2 - 32a + 9` from
`12a^2 + 60a -8`

When we write a from b this means b - a

So, for given polynomial written as ,

`12a^2 + 60a -8-(16a^2 - 32a + 9)`

Apply distribution, we have,

`-(16a^2 - 32a + 9)=-\left(16a^2\right)-\left(-32a\right)-\left(9\right)`

Apply plus - minus rule ,
`-\left(-a\right)=a,\:\:\:-\left(a\right)=-a` we have,

`=-16a^2+32a-9`

thus,
`12a^2 + 60a -8-(16a^2 - 32a + 9)` becomes,

`=12a^2+60a-8-16a^2+32a-9`

Adding similar terms, we have,

`=-4a^2+92a-17`

Thus,
`12a^2 + 60a -8-(16a^2 - 32a + 9)=-4a^2+92a-17`