Question

Which of the following polynomials has zeros at x = –4 and x = 7?

4x 2 - 7x - 11

4x 2 - 49

7x 2 - 4x + 28

x 2 - 3x - 28

Answer 1

The last one
x^2-3X-28
Z Z Z Z Z

Answer 2

Answer: The correct option is 4.

Step-by-step explanation:

It is given that the polynomial has two zeros at x=-4 and x=7.

If a polynomial has zeros at x=c then (x-c) is a factor of the polynomial.

Since the polynomial has two zeros at x=-4 and x=7, therefore the polynomial has factor (x+4) and (x-7).

`P(x)=(x+4)(x-7)`

`P(x)=x(x-7)+4(x-7)`

`P(x)=x^2-7x+4x-28`

`P(x)=x^2-3x-28`

This equation is represented by option 4, therefore the option 4 is correct and the equation
`P(x)=x^2-3x-28` has zeros at x = –4 and x = 7.