Question

12,14 and 16 are the length of the sides on the triangle

Heron’s formula: Area = square root s(s-a)(s-b)(s-c)

What is the area of triangle ABC? Round to the nearest hundredth of a square unit.

17.75 square units
81.33 square units
372.71 square units
957.74 square units

Answer 1

the answer is B)81.33 square units

Answer 2

Answer: 81.33 square units

Explanation:

Given sides of triangle = 12,14 and 16 are the a,b and c respectively.

Thus the perimeter of triangle
`=a+b+c=12+14+16=42`

The semi perimeter of triangle
`s=(42)/(2)=21`

By Heron's formula

Area of triangle =
`√(s(s-a)(s-b)(s-c))`

`=√(21(21-12)(21-14)(21-16))\\\\=√(21(9)(7)(5))\\\\=√(6615)\\=81.3326\approx81.33\text{ square units}`

The area of triangle =81.33 square units.